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Thread starter DonJuane Start date Aug 13, DonJuane New Member. Hello, I no longer work in IT but in the past I tried to learn Linux a few times but failed because it was just too complicated. I am trying to go both ways, first to encode the word "admin" and then decode it. I have tried this syntax on both the Linux systems I have access to and neither work. Test to make sure you can generate the same hash as the root account in the file by testing with 'admin'. Last edited: Aug 13, Gold Supporter.

G'day DonJuane and welcome to linux. Good luck Chris Turner wizardfromoz. With encryption its possible to go back to original password. With hashing on the other hand its a one way process. So you might ask if you can't get back to original password , how on for instance web gui login do you know when someone enters their password it a correct one? Does that make sense? SHA i believe was one of the first hash.

Thus you can't go back. Thanks for reply. So you say that there is no "reverse" to convert the long string of numbers starting with If I have the long number string above, even though it is "hashed" and not encrypted not sure if they are the same thing then having the long number string, there is no magic command string that can turn this long string back into the word "admin"? This stuff is over my head Check out this link to learn differences between encryption, hashing, and salting.

My best guess at the moment is What good would all this security be if it were all so simple to hack? I think its done is from many levels, knowing that keeping this stuff out of the user's hands allowing them to know their SIP phone ID and password that they pay monthly for keeps them from screwing up their router and generating a phone call to the support center when they mess it up. It's not actually a true security issue since I don't think a key is even involved.

It's like zipping something for a world that's never heard of zip. Downey 2. Johansson 2. Miller and David L. Odersky, L. Spoon, B. Hailperin, B. Kaiser, K. Harvey, M. Ducasse, L. Renggli, C. Shaffer, R. Dominik Hauser, Packt. Suchenwirth, et. You signed in with another tab or window. Reload to refresh your session. You signed out in another tab or window. Source code: Bits. Paste a list of words in the top text area or click Load dictionary to load one. Click "Encode" to create the trie and encode it. This step can be very slow, because I did not optimize the encoding process.

Once encoding is complete, you can use the Lookup button to check if words are in the dictionary.

Linux Terminal 201: Grep and Metacharacters - HakTip 159

Using this encoding method, a K dictionary containing words is compressed to K, or K gzipped. The browser does not need to decode it to use it. The whole trie takes as much space as a K string. Your browser does not support iframes Details The directory contains the information needed to compute the rank and select functions quickly. The trie is the bitstring representing the trie and the connections between all of its nodes. All of the bit decoding functions are configured to operated on BASE64 encoded units, so that the input string does not need to be decoded before being used.

We only handle the letters "a" to "z" in lower case. That way, we can encode each letter in 5 bits. This controls the number of bits summarized in each section of the rank directory. L2 is the maximum number of bits that have to be scanned to implement rank. More bits means fewer directory entries, but the select and rank functions will take longer to scan the range of bits. There is no known way to succinctly encode one.

You must store one pointer for each edge. This is because a trie does not compress common word endings together. Steve Hanov makes a living working on Rhymebrain. He lives in Waterloo, Canada.

Assembly Language Succinctly - Syncfusion by Chris Rose - PDF Drive

Post comment. What a great article, thank you so much! I hate to be "that guy," but I also can't stop myself: I think your Trie. If you add "bode," "bone," and "body" in that order , I think you wind up with two "d" Trienodes under the "o" node. Images are still badly missing! If you could revive them that would be very nice!

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Can you please good link the pictures in your article? Without pictures i don't good understand. Question: A very important point: How to map the path keys to hash? Correct me if I am wrong. The succinct representation just helps you in traversing the dictionary which is great bonus as you can exploit SIMD and other niceties. I think there is a mistake in your example It seems to me that it does and it's node's 4 children? Does this work on numbers?

I was trying to put in the first prime numbers and check if a number was prime Just like to point out that even if you tried to succinctly encode an MA-FSA, it would not improve asymptotically on the succinct trie. If you encode within its information theoretic optimum which succinct does then its impossible to improve on that. If you did, there would be some instances of trees that you could not encode.

MA-FSA are only useful in nonsuccint data structures. Because in information-theoretic terms pointers are a terrible way to encode trees. Obviously for speed and ease of use they are great! Just split it up into levels. Then its just a matter of encoding every possible combination of edges. Similar to tree but with obviously far more combinations.

I'm actually trying to compress a single file at the moment and i'm comparing the different algorithms which has been a load of fun. Very interesting.

Linux Succinctly

Does this encoding scheme support prefix search as well, or just membership tests? The Javascript code is released to the public domain. That means there is no copyright. You can put your name at the top and sell it as your own.

I don't care. Excellent blog post and wonderful Javascript code. Thank you. Is your Javascript code free for use? I did not see any copyright notices in it but wanted to make sure.

I have been in the field for over 25 years and it is amazing how there is new stuff to learn every day. Thanks again. But how efficient it is from informational perspective? I calculated frequencies for the trie -encoded scrabble dictionary: that is, how many nodes have exactly 0 children, how many nodes have 1 child, etc.